If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+x-212=0
a = 2; b = 1; c = -212;
Δ = b2-4ac
Δ = 12-4·2·(-212)
Δ = 1697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1697}}{2*2}=\frac{-1-\sqrt{1697}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1697}}{2*2}=\frac{-1+\sqrt{1697}}{4} $
| 2b^2+7b-4=0 | | 2x+8+2x+8=28 | | 3×x-8=5×x+10 | | 5x-3÷x=102 | | 2×x+1=4×-5 | | 2×x+1=4× | | 3(u+2)-7u=14 | | 31/3y+4=16 | | -(x+6)(x+4)=x(x+11+6)- | | 2b^2-7b+6=3 | | 10-(2y/3)=5 | | -7(x+4)+2×+7=8x+6 | | -24p-5(5-6p)=4(p-2)-13 | | 6x+3(-3-5)=-12-6x | | a+2122=365 | | 4^2+9^2=c^2 | | 3x2-7=1 | | 100(1+0.2P+0.02P^2)t=18 | | =100(1+0.2P+0.02P^2)t=18 | | 5x+35(440-x)=1780 | | P=100(1+0.2t+0.02t^2) | | 12x-5=4x+43 | | 3x^2-7=1 | | C(t)=31.5-0.35t^2 | | -7v+4(v-8)=-26 | | 5.5-x=3.4 | | 0.9+x=x+20 | | 20(x-4)=8(x+3.5) | | X-4(20)=x+3.5(8) | | (+2x^2-7x+4x-14)(2x+3)=117 | | (x+2)(2x-7)(2x+3)=117 | | X=y^2-10y+24 |